(20x^2-11x-4)=0

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Solution for (20x^2-11x-4)=0 equation:


Simplifying
(20x2 + -11x + -4) = 0

Reorder the terms:
(-4 + -11x + 20x2) = 0

Remove parenthesis around (-4 + -11x + 20x2)
-4 + -11x + 20x2 = 0

Solving
-4 + -11x + 20x2 = 0

Solving for variable 'x'.

Factor a trinomial.
(-1 + -4x)(4 + -5x) = 0

Subproblem 1

Set the factor '(-1 + -4x)' equal to zero and attempt to solve: Simplifying -1 + -4x = 0 Solving -1 + -4x = 0 Move all terms containing x to the left, all other terms to the right. Add '1' to each side of the equation. -1 + 1 + -4x = 0 + 1 Combine like terms: -1 + 1 = 0 0 + -4x = 0 + 1 -4x = 0 + 1 Combine like terms: 0 + 1 = 1 -4x = 1 Divide each side by '-4'. x = -0.25 Simplifying x = -0.25

Subproblem 2

Set the factor '(4 + -5x)' equal to zero and attempt to solve: Simplifying 4 + -5x = 0 Solving 4 + -5x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -5x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -5x = 0 + -4 -5x = 0 + -4 Combine like terms: 0 + -4 = -4 -5x = -4 Divide each side by '-5'. x = 0.8 Simplifying x = 0.8

Solution

x = {-0.25, 0.8}

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